Ruby程序中发送基于HTTP协议的请求的简单示例_ruby专题_

 require "open-uri" #如果有GET请求参数直接写在URI地址中 uri = 'http://uri' html_response = nil open(uri) do |http| html_response = http.read end puts html_response require "open-uri" #如果有GET请求参数直接写在URI地址中 uri = 'http://uri' html_response = nil open(uri) do |http| html_response = http.read end puts html_response 

 params = {} params["name"] = 'Tom' uri = URI.parse("http://uri") res = Net::HTTP.post_form (uri, params) #返回的cookie puts res.header['set-cookie'] #返回的html body puts res.body params = {} params["name"] = 'Tom' uri = URI.parse("http://uri") res = Net::HTTP.post_form (uri, params) #返回的cookie puts res.header['set-cookie'] #返回的html body puts res.body 

 # # 描述： # 发送快递数据到datasystem,使用https # 输入： # data - 组装后的expess的数据 # 输出： # datasystem返回的状态信息 # def self.senddatassl(url,data) url = url + data $logger.info(url) begin uri = URI.parse(URI.escape(url)) http = Net::HTTP.new(uri.host, uri.port) http.use_ssl = true if ($logger != nil) $logger.info("链接地址参数:#{URI.escape(url)},文件名：#{__FILE__},第 #{__LINE__} 行") $logger.info("传入data参数:#{data.to_json},文件名：#{__FILE__},第 #{__LINE__} 行") end request = Net::HTTP::Get.new(uri.request_uri) response = http.request(request) rescue =>exception $logger.error("传递url地址为#{url}，错误!#{exception.to_s},文件名：#{__FILE__},第 #{__LINE__} 行") return nil end return response.body end